What is the circumference (x-3)^2+(y-2)^2=2 ?

The circumference (x-3)^2+(y-2)^2=2 is C=2sqrt(2)pi

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circumference (x-3)^2+(y-2)^2=2

circumference

(x - 3)^{2} + (y - 2)^{2} = 2

C = 22 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 3)^{2} + (y - 2)^{2} = 2 : r = 2

C = 22 π

(x + 7)^{2} + (y - 1)^{2} = 8

c i rc l e, f in d C i rc u m f ere n ce, g i v e n r = 7

x^{2} + y^{2} - 6 x + 2 y - 1 = 0

x^{2} + y^{2} = - 2 x

(x - 4)^{2} + (y + 4)^{2} = 36

What is the circumference (x-3)^2+(y-2)^2=2 ?
The circumference (x-3)^2+(y-2)^2=2 is C=2sqrt(2)pi