What is the circumference 4x^2+16x+15+4y^2+6y=0 ?

The circumference 4x^2+16x+15+4y^2+6y=0 is C=(sqrt(13)pi)/2

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circumference 4x^2+16x+15+4y^2+6y=0

circumference

4 x^{2} + 16 x + 15 + 4 y^{2} + 6 y = 0

C = \frac{13 π}{2}

Solution steps

C = 2 π r

Find the radius

Radius given

4 x^{2} + 16 x + 15 + 4 y^{2} + 6 y = 0 : r = \frac{13}{4}

C = 2 π \frac{13}{4}

Refine

C = \frac{13 π}{2}

x^{2} + y^{2} - 10 x - 6 y + 9 = 0

(x - 1)^{2} + (y - 2)^{2} = 3^{2}

(x - 5)^{2} + (y - 9)^{2} = 4

(x - 3)^{2} + (y - 3)^{2} = 7

(x - 5)^{2} + y^{2} = 4

What is the circumference 4x^2+16x+15+4y^2+6y=0 ?
The circumference 4x^2+16x+15+4y^2+6y=0 is C=(sqrt(13)pi)/2