What is the circumference (x-6)^2+(y-4)^2=5^2 ?

The circumference (x-6)^2+(y-4)^2=5^2 is C=10pi

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circumference (x-6)^2+(y-4)^2=5^2

circumference

(x - 6)^{2} + (y - 4)^{2} = 5^{2}

C = 10 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 6)^{2} + (y - 4)^{2} = 5^{2} : r = 5

C = 2 π 5

Refine

C = 10 π

(x - 4)^{2} + (y + 2)^{2} = 49

x^{2} + y^{2} - 4 x = 0

x^{2} + y^{2} + 4 x - 2 y + 1 = 0

(x - 1)^{2} + y^{2} = 4

(x + 2)^{2} + (y - 1)^{2} = 25

What is the circumference (x-6)^2+(y-4)^2=5^2 ?
The circumference (x-6)^2+(y-4)^2=5^2 is C=10pi