What is the circumference 4x^2+4y^2-4x+8y-11=0 ?

The circumference 4x^2+4y^2-4x+8y-11=0 is C=4pi

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circumference 4x^2+4y^2-4x+8y-11=0

circumference

4 x^{2} + 4 y^{2} - 4 x + 8 y - 11 = 0

C = 4 π

Solution steps

C = 2 π r

Find the radius

Radius given

4 x^{2} + 4 y^{2} - 4 x + 8 y - 11 = 0 : r = 2

C = 2 π 2

Refine

C = 4 π

x^{2} + y^{2} + 5 x + 20 y + 10 = 0

x^{2} + y^{2} + 2 x + 6 y - 104 = 0

(x - \frac{1}{2})^{2} + (y - \frac{3}{2})^{2} = 1

x^{2} + y^{2} - 4 x + 6 y + 4 = 0

x^{2} + y^{2} - 6 x - 4 y + 9 = 0

What is the circumference 4x^2+4y^2-4x+8y-11=0 ?
The circumference 4x^2+4y^2-4x+8y-11=0 is C=4pi