What is the circumference (x+1)^2+(y+1)^2=sqrt(13) ?

The circumference (x+1)^2+(y+1)^2=sqrt(13) is C=2\sqrt[4]{13}pi

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circumference (x+1)^2+(y+1)^2=sqrt(13)

circumference

(x + 1)^{2} + (y + 1)^{2} = 13

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 1)^{2} + (y + 1)^{2} = 13 : r = 13

C = 2 π 13

Refine

x^{2} + y^{2} = 7 + x

x^{2} + y^{2} - 4 x - 5 = 0

x^{2} - 3 x + y^{2} + 1 = 0

(x - 2)^{2} + y^{2} = 6

(x - 9)^{2} + (y + 4)^{2} = 25

What is the circumference (x+1)^2+(y+1)^2=sqrt(13) ?
The circumference (x+1)^2+(y+1)^2=sqrt(13) is C=2\sqrt[4]{13}pi