en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference x^2+y^2+8x+2y+1=0

Solution

circumference

x^{2} + y^{2} + 8 x + 2 y + 1 = 0

Solution

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 8 x + 2 y + 1 = 0 : r = 4

C = 2 π 4

Refine

C = 8 π

Popular Examples

circumference x^2+y^2+14y+13=0 circumference

x^{2} + y^{2} + 14 y + 13 = 0

circumference (x-3)^2+(y-2)^2=25 circumference

(x - 3)^{2} + (y - 2)^{2} = 25

circumference x^2+(y-1)^2=1 circumference

x^{2} + (y - 1)^{2} = 1

circle, find Circumference, given r=2x-4

c i rc l e, f in d C i rc u m f ere n ce, g i v e n r = 2 x - 4

circumference x^2+y^2-2x+4y-21=0 circumference

x^{2} + y^{2} - 2 x + 4 y - 21 = 0

Frequently Asked Questions (FAQ)

What is the circumference x^2+y^2+8x+2y+1=0 ?
The circumference x^2+y^2+8x+2y+1=0 is C=8pi