en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference x^2+y^2<= 4^2

Solution

circumference

x^{2} + y^{2} \leq 4^{2}

Solution

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} \leq 4^{2} : r = 4

C = 2 π 4

Refine

C = 8 π

Popular Examples

circumference (x-4)^2+y^2=8 circumference

(x - 4)^{2} + y^{2} = 8

circumference x^2=-y^2+4 circumference

x^{2} = - y^{2} + 4

circumference x^2+(y-6)^2=9 circumference

x^{2} + (y - 6)^{2} = 9

circumference (x-1)^2+(y-3)^2=2^2 circumference

(x - 1)^{2} + (y - 3)^{2} = 2^{2}

diameter (x-0)^2+(y-20)^2=400 diameter

(x - 0)^{2} + (y - 20)^{2} = 400

Frequently Asked Questions (FAQ)

What is the circumference x^2+y^2<= 4^2 ?
The circumference x^2+y^2<= 4^2 is C=8pi