en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

diameter x^2+y^2+6x-4y-23=0

Solution

diameter

x^{2} + y^{2} + 6 x - 4 y - 23 = 0

Solution

d = 12

Solution steps

d = 2 r

Find the radius

Radius given

x^{2} + y^{2} + 6 x - 4 y - 23 = 0 : r = 6

d = 2 \cdot 6

Refine

d = 12

Popular Examples

diameter x^2+y^2+6x-2y-15=0 diameter

x^{2} + y^{2} + 6 x - 2 y - 15 = 0

diameter (x+2)^2+(y-4)^2=25 diameter

(x + 2)^{2} + (y - 4)^{2} = 25

diameter x^2+2x+y^2+4y=20 diameter

x^{2} + 2 x + y^{2} + 4 y = 20

diameter x^2+y^2=20 diameter

x^{2} + y^{2} = 20

diameter (x-2)^2+y^2=16 diameter

(x - 2)^{2} + y^{2} = 16

Frequently Asked Questions (FAQ)

What is the diameter x^2+y^2+6x-4y-23=0 ?
The diameter x^2+y^2+6x-4y-23=0 is d=12