What is the diameter 36x^2+36y^2-12x-27y-8=0 ?

The diameter 36x^2+36y^2-12x-27y-8=0 is d=1.25

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diameter 36x^2+36y^2-12x-27y-8=0

diameter

36 x^{2} + 36 y^{2} - 12 x - 27 y - 8 = 0

d = 1.25

Solution steps

d = 2 r

Find the radius

Radius given

36 x^{2} + 36 y^{2} - 12 x - 27 y - 8 = 0 : r = \frac{5}{8}

d = 2 \cdot \frac{5}{8}

Refine

d = 1.25

x^{2} + y^{2} = 4 \frac{2}{2}

2 x^{2} + 2 y^{2} = 16

x^{2} + y^{2} + 3 x - 5 y + 1 = 0

x^{2} + y^{2} - 2 x - 6 y - 15 = 0

\frac{( y - 2 ) ^{2}}{9} + \frac{( x + \frac{1}{2} ) ^{2}}{9} = 1

What is the diameter 36x^2+36y^2-12x-27y-8=0 ?
The diameter 36x^2+36y^2-12x-27y-8=0 is d=1.25