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Popular >

diameter 2x^2+2y^2+x=0

Solution

diameter

2 x^{2} + 2 y^{2} + x = 0

Solution

d = 0.5

Solution steps

d = 2 r

Find the radius

Radius given

2 x^{2} + 2 y^{2} + x = 0 : r = \frac{1}{4}

d = 2 \cdot \frac{1}{4}

Refine

d = 0.5

Popular Examples

area 3.5(x+2.2)^2+3.5(y-11.1)^2-21=0 area

3.5 (x + 2.2)^{2} + 3.5 (y - 11.1)^{2} - 21 = 0

area x^2+y^2=36 area

x^{2} + y^{2} = 36

area x^2+y^2=81 area

x^{2} + y^{2} = 81

area x^2+y^2=9 area

x^{2} + y^{2} = 9

area 3x^2+3y^2+2x-4y-1=0 area

3 x^{2} + 3 y^{2} + 2 x - 4 y - 1 = 0

Frequently Asked Questions (FAQ)

What is the diameter 2x^2+2y^2+x=0 ?
The diameter 2x^2+2y^2+x=0 is d=0.5