What is the area 100x^2+100y^2-100x+400y+409=0 ?

The area 100x^2+100y^2-100x+400y+409=0 is A=(4pi)/(25)

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area 100x^2+100y^2-100x+400y+409=0

area

100 x^{2} + 100 y^{2} - 100 x + 400 y + 409 = 0

A = \frac{4 π}{25}

Solution steps

A = π r^{2}

Find the radius

Radius given

100 x^{2} + 100 y^{2} - 100 x + 400 y + 409 = 0 : r = \frac{2}{5}

A = π (\frac{2}{5})^{2}

Refine

A = \frac{4 π}{25}

x^{2} + y^{2} = 25

x^{2} + y^{2} = 121

x^{2} + y^{2} - 8 x - 6 y - 11 = 0

x^{2} + 14 x + y^{2} - 6 y - 23 = 0

3 x^{2} + 3 y^{2} = 75

What is the area 100x^2+100y^2-100x+400y+409=0 ?
The area 100x^2+100y^2-100x+400y+409=0 is A=(4pi)/(25)