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Popular >

area 2x^2+2y^2+2x-y=0

Solution

area

2 x^{2} + 2 y^{2} + 2 x - y = 0

Solution

A = \frac{5 π}{16}

Solution steps

A = π r^{2}

Find the radius

Radius given

2 x^{2} + 2 y^{2} + 2 x - y = 0 : r = \frac{5}{4}

A = π (\frac{5}{4})^{2}

Refine

A = \frac{5 π}{16}

Popular Examples

area x^2+y^2+6x-4y+3=0 area

x^{2} + y^{2} + 6 x - 4 y + 3 = 0

area x^2-6x+y^2+8y=0 area

x^{2} - 6 x + y^{2} + 8 y = 0

area x^2+y^2=100 area

x^{2} + y^{2} = 100

area (x-5)^2+(y-9)^2=4 area

(x - 5)^{2} + (y - 9)^{2} = 4

area 1/2 x^2+1/2 y^2=16 area

\frac{1}{2} x^{2} + \frac{1}{2} y^{2} = 16

Frequently Asked Questions (FAQ)

What is the area 2x^2+2y^2+2x-y=0 ?
The area 2x^2+2y^2+2x-y=0 is A=(5pi)/(16)