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Popular >

area x^2+y^2> 1/2

Solution

area

x^{2} + y^{2} > \frac{1}{2}

Solution

A = \frac{π}{2}

Solution steps

A = π r^{2}

Find the radius

Radius given

x^{2} + y^{2} > \frac{1}{2} : r = \frac{1}{2}

A = π (\frac{1}{2})^{2}

Refine

A = \frac{π}{2}

Popular Examples

area x^2+(y-7)^2=36 area

x^{2} + (y - 7)^{2} = 36

area x^2+y^2+6x-4y-23=0 area

x^{2} + y^{2} + 6 x - 4 y - 23 = 0

area x^2+y^2=12 area

x^{2} + y^{2} = 12

area x^2-2x+y^2+2y=7 area

x^{2} - 2 x + y^{2} + 2 y = 7

area (x+2)^2+(y-4)^2=25 area

(x + 2)^{2} + (y - 4)^{2} = 25

Frequently Asked Questions (FAQ)

What is the area x^2+y^2> 1/2 ?
The area x^2+y^2> 1/2 is A= pi/2