What is x^2+(y^2)/9 =1 ?

The solution to x^2+(y^2)/9 =1 is Ellipse with (h,k)=(0,0),a=1,b=3

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x^2+(y^2)/9 =1

x^{2} + \frac{y ^{2}}{9} = 1

(h, k) = (0, 0), a = 1, b = 3

Solution steps

x^{2} + \frac{y ^{2}}{9} = 1

Rewrite

x^{2} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 3, a = 1

4 x^{2} + 9 y^{2} - 16 x + 18 y - 11 = 0

3 x^{2} + y^{2} - 24 x + 39 = 0

9 x^{2} + 16 y^{2} - 54 x + 64 y + 1 = 0

\frac{( x - 4 ) ^{2}}{2} + \frac{( y - 3 ) ^{2}}{1} = 1

\frac{( x - 2 ) ^{2}}{36} + \frac{( y + 5 ) ^{2}}{9} = 1

What is x^2+(y^2)/9 =1 ?
The solution to x^2+(y^2)/9 =1 is Ellipse with (h,k)=(0,0),a=1,b=3