What is x^2+(y^2)/4 =1 ?

The solution to x^2+(y^2)/4 =1 is Ellipse with (h,k)=(0,0),a=1,b=2

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x^2+(y^2)/4 =1

x^{2} + \frac{y ^{2}}{4} = 1

(h, k) = (0, 0), a = 1, b = 2

Solution steps

x^{2} + \frac{y ^{2}}{4} = 1

Rewrite

x^{2} + \frac{y ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 2, a = 1

x^{2} + 4 y^{2} + 7 = 12 y - 2 x

\frac{x ^{2}}{16} + (y - 4)^{2} = 1

\frac{x ^{2}}{169} + \frac{y ^{2}}{144} = 1

x^{2} + 2 y^{2} + 2 x - 20 y + 43 = 0

9 x^{2} + 49 y^{2} - 144 x + 490 y + 1360 = 0

What is x^2+(y^2)/4 =1 ?
The solution to x^2+(y^2)/4 =1 is Ellipse with (h,k)=(0,0),a=1,b=2