What is (x^2)/(49)+(y^2)/(36)=1 ?

The solution to (x^2)/(49)+(y^2)/(36)=1 is Ellipse with (h,k)=(0,0),a=7,b=6

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(x^2)/(49)+(y^2)/(36)=1

\frac{x ^{2}}{49} + \frac{y ^{2}}{36} = 1

(h, k) = (0, 0), a = 7, b = 6

Solution steps

\frac{x ^{2}}{49} + \frac{y ^{2}}{36} = 1

Rewrite

\frac{x ^{2}}{49} + \frac{y ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 7, b = 6

9 x^{2} + 4 y^{2} + 18 x - 8 y - 131 = 0

2 x^{2} - 8 x + y^{2} + 6 y + 15 = 0

8 x^{2} + 2 y^{2} - 12 = 0

x^{2} + 4 y^{2} + 2 x - 12 y + 2 = 0

\frac{( x - 5 ) ^{2}}{25} + \frac{( y + 7 ) ^{2}}{16} = 1

What is (x^2)/(49)+(y^2)/(36)=1 ?
The solution to (x^2)/(49)+(y^2)/(36)=1 is Ellipse with (h,k)=(0,0),a=7,b=6