What is x^2+y^2-y=0 ?

The solution to x^2+y^2-y=0 is Ellipse with (h,k)=(0, 1/2),a= 1/2 ,b= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-y=0

x^{2} + y^{2} - y = 0

(h, k) = (0, \frac{1}{2}), a = \frac{1}{2}, b = \frac{1}{2}

Solution steps

x^{2} + y^{2} - y = 0

Rewrite

x^{2} + y^{2} - y = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{1}{2} ) ^{2}} + \frac{( y - \frac{1}{2} ) ^{2}}{( \frac{1}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, \frac{1}{2}), a = \frac{1}{2}, b = \frac{1}{2}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, \frac{1}{2}), b = \frac{1}{2}, a = \frac{1}{2}

9 x^{2} - 18 x + 4 y^{2} = 27

2 x^{2} + y^{2} - 4 x + 6 y + 3 = 0

25 x^{2} + 4 y^{2} - 250 x - 16 y + 541 = 0

x^{2} + 4 y^{2} - 6 x + 8 y + 9 = 0

16 x^{2} + 25 y^{2} - 96 x + 100 y - 156 = 0

What is x^2+y^2-y=0 ?
The solution to x^2+y^2-y=0 is Ellipse with (h,k)=(0, 1/2),a= 1/2 ,b= 1/2