What is ((x-1)^2)/4+((y+2)^2)/(16)=1 ?

The solution to ((x-1)^2)/4+((y+2)^2)/(16)=1 is Ellipse with (h,k)=(1,-2),a=2,b=4

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((x-1)^2)/4+((y+2)^2)/(16)=1

\frac{( x - 1 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{16} = 1

(h, k) = (1, - 2), a = 2, b = 4

Solution steps

\frac{( x - 1 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{2 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, - 2), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, - 2), b = 4, a = 2

x^{2} + 4 y^{2} - 6 x + 5 = 0

\frac{( x - 2 ) ^{2}}{25} + \frac{( y + 3 ) ^{2}}{9} = 1

x^{2} + 9 y^{2} = 36

x^{2} + 9 y^{2} = 1

\frac{y ^{2}}{25} + \frac{x ^{2}}{9} = 1

What is ((x-1)^2)/4+((y+2)^2)/(16)=1 ?
The solution to ((x-1)^2)/4+((y+2)^2)/(16)=1 is Ellipse with (h,k)=(1,-2),a=2,b=4