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Popular >

4x^2+y^2-16x+15=0

Solution

4 x^{2} + y^{2} - 16 x + 15 = 0

Solution

(h, k) = (2, 0), a = \frac{1}{2}, b = 1

Solution steps

4 x^{2} + y^{2} - 16 x + 15 = 0

Rewrite

4 x^{2} + y^{2} - 16 x + 15 = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{( \frac{1}{2} ) ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 0), a = \frac{1}{2}, b = 1

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, 0), b = 1, a = \frac{1}{2}

Popular Examples

((x-1)^2)/(45)+((y-2)^2)/(20)=1

\frac{( x - 1 ) ^{2}}{45} + \frac{( y - 2 ) ^{2}}{20} = 1

4x^2+36y^2-24x-288y+611=0

4 x^{2} + 36 y^{2} - 24 x - 288 y + 611 = 0

(x^2)/8+(y^2)/(12)=1

\frac{x ^{2}}{8} + \frac{y ^{2}}{12} = 1

7 x^{2} + 2 y^{2} - 14 = 0

((x-3)^2}{16}+\frac{(y+1)^2)/4 =1

\frac{( x - 3 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{4} = 1

Frequently Asked Questions (FAQ)

What is 4x^2+y^2-16x+15=0 ?
The solution to 4x^2+y^2-16x+15=0 is Ellipse with (h,k)=(2,0),a= 1/2 ,b=1