What is ((x+1)^2)/9+((y-2)^2)/4 =1 ?

The solution to ((x+1)^2)/9+((y-2)^2)/4 =1 is Ellipse with (h,k)=(-1,2),a=3,b=2

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((x+1)^2)/9+((y-2)^2)/4 =1

\frac{( x + 1 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{4} = 1

(h, k) = (- 1, 2), a = 3, b = 2

Solution steps

\frac{( x + 1 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{4} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{3 ^{2}} + \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 2), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1, 2), a = 3, b = 2

\frac{( x - 3 ) ^{2}}{16} + \frac{( y + 4 ) ^{2}}{9} = 1

9 x^{2} + 4 y^{2} + 18 x - 16 y - 11 = 0

3 x^{2} + 2 y^{2} - 12 x + 8 y + 19 = 0

\frac{( x + 1 ) ^{2}}{4} + \frac{( y - 5 ) ^{2}}{9} = 1

\frac{( x + 5 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{25} = 1

What is ((x+1)^2)/9+((y-2)^2)/4 =1 ?
The solution to ((x+1)^2)/9+((y-2)^2)/4 =1 is Ellipse with (h,k)=(-1,2),a=3,b=2