What is 2x^2+2y^2-2x-2y-3=0 ?

The solution to 2x^2+2y^2-2x-2y-3=0 is Circle with (a,b)=(1/2 , 1/2),r=sqrt(2)

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2x^2+2y^2-2x-2y-3=0

2 x^{2} + 2 y^{2} - 2 x - 2 y - 3 = 0

(a, b) = (\frac{1}{2}, \frac{1}{2}), r = 2

Solution steps

2 x^{2} + 2 y^{2} - 2 x - 2 y - 3 = 0

Rewrite

2 x^{2} + 2 y^{2} - 2 x - 2 y - 3 = 0

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, \frac{1}{2}), r = 2

\frac{x ^{2}}{36} + \frac{y ^{2}}{25} = 1

x^{2} + y^{2} - 2 y = 0

9 x^{2} - 9 y^{2} + 18 x + 36 y = 63

y^{2} = 28 x

\frac{x ^{2}}{64} - \frac{y ^{2}}{9} = 1

What is 2x^2+2y^2-2x-2y-3=0 ?
The solution to 2x^2+2y^2-2x-2y-3=0 is Circle with (a,b)=(1/2 , 1/2),r=sqrt(2)