What is ((x-2)^2)/(26)+((y-3)^2)/(81)=1 ?

The solution to ((x-2)^2)/(26)+((y-3)^2)/(81)=1 is Ellipse with (h,k)=(2,3),a=sqrt(26),b=9

Popular >

((x-2)^2)/(26)+((y-3)^2)/(81)=1

\frac{( x - 2 ) ^{2}}{26} + \frac{( y - 3 ) ^{2}}{81} = 1

(h, k) = (2, 3), a = 26, b = 9

Solution steps

\frac{( x - 2 ) ^{2}}{26} + \frac{( y - 3 ) ^{2}}{81} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{26} + \frac{( y - 3 ) ^{2}}{81} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{( 26 ) ^{2}} + \frac{( y - 3 ) ^{2}}{9 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 3), a = 26, b = 9

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, 3), b = 9, a = 26

2 x^{2} + 2 y^{2} + 20 y = 0

4 x^{2} + y^{2} - 6 y = 27

8 x^{2} + 16 x + 2 y^{2} = 0

4 x^{2} + 36 y^{2} + 24 x + 432 y = - 1188

\frac{( x - 3 ) ^{2}}{100} + \frac{( y + 4 ) ^{2}}{64} = 1

What is ((x-2)^2)/(26)+((y-3)^2)/(81)=1 ?
The solution to ((x-2)^2)/(26)+((y-3)^2)/(81)=1 is Ellipse with (h,k)=(2,3),a=sqrt(26),b=9