What is ((x^2))/4+y^2 1/9 =1 ?

The solution to ((x^2))/4+y^2 1/9 =1 is Ellipse with (h,k)=(0,0),a=2,b=3

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((x^2))/4+y^2 1/9 =1

\frac{( x ^{2} )}{4} + y^{2} \frac{1}{9} = 1

(h, k) = (0, 0), a = 2, b = 3

Solution steps

\frac{x ^{2}}{4} + y^{2} \frac{1}{9} = 1

Rewrite

\frac{x ^{2}}{4} + y^{2} \frac{1}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 3, a = 2

9 x^{2} + 4 y^{2} + 36 x + 24 y + 36 = 0

x^{2} + 4 y^{2} - 80 y + 143 = 0

9 x^{2} + 8 y^{2} - 54 x - 16 y + 17 = 0

x^{2} + 2 y^{2} - 3 x + 2 y - 2 = 0

81 x^{2} + 9 y^{2} = 9

What is ((x^2))/4+y^2 1/9 =1 ?
The solution to ((x^2))/4+y^2 1/9 =1 is Ellipse with (h,k)=(0,0),a=2,b=3