What is (x^2)/2+(y^2)/5 =1 ?

The solution to (x^2)/2+(y^2)/5 =1 is Ellipse with (h,k)=(0,0),a=sqrt(2),b=sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2)/2+(y^2)/5 =1

\frac{x ^{2}}{2} + \frac{y ^{2}}{5} = 1

(h, k) = (0, 0), a = 2, b = 5

Solution steps

\frac{x ^{2}}{2} + \frac{y ^{2}}{5} = 1

Rewrite

\frac{x ^{2}}{2} + \frac{y ^{2}}{5} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 5 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 2

- \frac{x ^{2}}{25} - \frac{y ^{2}}{16} = 1

x^{2} + 2 y^{2} - 2 x - 4 y - 8 = 0

7 x^{2} + 25 y^{2} = 175

\frac{( x - 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{9} = 1

x^{2} + 5 y^{2} = 9 (2.1)

What is (x^2)/2+(y^2)/5 =1 ?
The solution to (x^2)/2+(y^2)/5 =1 is Ellipse with (h,k)=(0,0),a=sqrt(2),b=sqrt(5)