What is x^2+2y^2-2x-4y=-1 ?

The solution to x^2+2y^2-2x-4y=-1 is Ellipse with (h,k)=(1,1),a=sqrt(2),b=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+2y^2-2x-4y=-1

x^{2} + 2 y^{2} - 2 x - 4 y = - 1

(h, k) = (1, 1), a = 2, b = 1

Solution steps

x^{2} + 2 y^{2} - 2 x - 4 y = - 1

Rewrite

x^{2} + 2 y^{2} - 2 x - 4 y = - 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{( 2 ) ^{2}} + \frac{( y - 1 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 1), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 1), a = 2, b = 1

2 x^{2} + y^{2} \leq 1

\frac{x ^{2}}{7 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

16 x^{2} + 25 y^{2} - 64 x + 150 y = - 279

4 x^{2} + y^{2} - 40 x + 4 y + 68 = 0

x^{2} + 2 x = - 4 y^{2} + 12 y + 7

What is x^2+2y^2-2x-4y=-1 ?
The solution to x^2+2y^2-2x-4y=-1 is Ellipse with (h,k)=(1,1),a=sqrt(2),b=1