What is x^2+12x+3/2 y+39=0 ?

The solution to x^2+12x+3/2 y+39=0 is Parabola with (h,k)=(-6,-2),p=-3/8

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x^2+12x+3/2 y+39=0

x^{2} + 12 x + \frac{3}{2} y + 39 = 0

(h, k) = (- 6, - 2), p = - \frac{3}{8}

Solution steps

x^{2} + 12 x + \frac{3}{2} y + 39 = 0

Rewrite

x^{2} + 12 x + \frac{3}{2} y + 39 = 0

in the standard form

4 (- \frac{3}{8}) (y - (- 2)) = (x - (- 6))^{2}

Therefore parabola properties are:

(h, k) = (- 6, - 2), p = - \frac{3}{8}

x^{2} + y - 25 = 0

x = 4 y - y^{2}

8 x = y^{2}

2 - y - x^{2} > 0

5 a^{2} = 48 b

What is x^2+12x+3/2 y+39=0 ?
The solution to x^2+12x+3/2 y+39=0 is Parabola with (h,k)=(-6,-2),p=-3/8