What is (x^2)/(2^2)+(y^2)/(3^2)=1 ?

The solution to (x^2)/(2^2)+(y^2)/(3^2)=1 is Ellipse with (h,k)=(0,0),a=2,b=3

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(x^2)/(2^2)+(y^2)/(3^2)=1

\frac{x ^{2}}{2 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

(h, k) = (0, 0), a = 2, b = 3

Solution steps

\frac{x ^{2}}{2 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

Rewrite

\frac{x ^{2}}{2 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 3, a = 2

2 x^{2} + 2 y^{2} - 24 y = 0

y^{2} + 4 x^{2} = 128

2 x^{2} + 3 y^{2} + 10 x + 9 y - 19 = 0

2 (x - 3)^{2} + 3 (y - 2)^{2} = 6

(\frac{x ^{2}}{15}) + ((\frac{( y - 8 )}{49})^{2}) = 1

What is (x^2)/(2^2)+(y^2)/(3^2)=1 ?
The solution to (x^2)/(2^2)+(y^2)/(3^2)=1 is Ellipse with (h,k)=(0,0),a=2,b=3