What is ((x-2)^2)/(100)+(y^2)/(36)=1 ?

The solution to ((x-2)^2)/(100)+(y^2)/(36)=1 is Ellipse with (h,k)=(2,0),a=10,b=6

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((x-2)^2)/(100)+(y^2)/(36)=1

\frac{( x - 2 ) ^{2}}{100} + \frac{y ^{2}}{36} = 1

(h, k) = (2, 0), a = 10, b = 6

Solution steps

\frac{( x - 2 ) ^{2}}{100} + \frac{y ^{2}}{36} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{100} + \frac{y ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{1 0 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 0), a = 10, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, 0), a = 10, b = 6

\frac{( x + 2 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{49} = 1

\frac{( x - 1 ) ^{2}}{36} + \frac{( y + 2 ) ^{2}}{16} = 1

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{25} = 1

3 X^{2} + 2 Y^{2} = 8

9 x^{2} + 36 y^{2} = 324

What is ((x-2)^2)/(100)+(y^2)/(36)=1 ?
The solution to ((x-2)^2)/(100)+(y^2)/(36)=1 is Ellipse with (h,k)=(2,0),a=10,b=6