What is 3x^2+y^2=52 ?

The solution to 3x^2+y^2=52 is Ellipse with (h,k)=(0,0),a=(2sqrt(13))/(sqrt(3)),b=2sqrt(13)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3x^2+y^2=52

3 x^{2} + y^{2} = 52

(h, k) = (0, 0), a = \frac{2 13}{3}, b = 213

Solution steps

3 x^{2} + y^{2} = 52

Rewrite

3 x^{2} + y^{2} = 52

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{2 13}{3} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 13 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{2 13}{3}, b = 213

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 213, a = \frac{2 13}{3}

(\frac{x ^{2}}{25}) + (\frac{y ^{2}}{9}) = 1

8 x^{2} + 16 x + 4 y^{2} - 12 y = 15

\frac{( x + 2 ) ^{2}}{16} + \frac{( y - 4 ) ^{2}}{9} = 1

\frac{x ^{2}}{400} + \frac{y ^{2}}{256} = 1

3 x^{2} + y^{2} - 25 = 0

What is 3x^2+y^2=52 ?
The solution to 3x^2+y^2=52 is Ellipse with (h,k)=(0,0),a=(2sqrt(13))/(sqrt(3)),b=2sqrt(13)