What is (x-9)^2+(y-3)=64 ?

The solution to (x-9)^2+(y-3)=64 is Parabola with (h,k)=(9,67),p=-1/4

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(x-9)^2+(y-3)=64

(x - 9)^{2} + (y - 3) = 64

(h, k) = (9, 67), p = - \frac{1}{4}

Solution steps

(x - 9)^{2} + (y - 3) = 64

Rewrite

(x - 9)^{2} + (y - 3) = 64

in the standard form:

4 (- \frac{1}{4}) (y - 67) = (x - 9)^{2}

Therefore parabola properties are:

(h, k) = (9, 67), p = - \frac{1}{4}

x^{2} = y - 2

x^{2} + 2 y = 4

x^{2} - 4 x + 12 y = 20

(x - 3)^{2} = - 6 (y + 1)

(y + 2)^{2} = 2 x + 8

What is (x-9)^2+(y-3)=64 ?
The solution to (x-9)^2+(y-3)=64 is Parabola with (h,k)=(9,67),p=-1/4