What is 2x^2+10y^2=20 ?

The solution to 2x^2+10y^2=20 is Ellipse with (h,k)=(0,0),a=sqrt(10),b=sqrt(2)

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2x^2+10y^2=20

2 x^{2} + 10 y^{2} = 20

(h, k) = (0, 0), a = 10, b = 2

Solution steps

2 x^{2} + 10 y^{2} = 20

Rewrite

2 x^{2} + 10 y^{2} = 20

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 10 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 10, b = 2

9 x^{2} + 4 y^{2} - 8 y - 32 = 0

\frac{x ^{2}}{36} + \frac{8 y ^{2}}{81} = 1

3 x^{2} + 7 y^{2} = 1

4 x^{2} + 9 y^{2} - 16 x - 36 y + 16 = 0

\frac{( x + 2 ) ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

What is 2x^2+10y^2=20 ?
The solution to 2x^2+10y^2=20 is Ellipse with (h,k)=(0,0),a=sqrt(10),b=sqrt(2)