What is (x-2)^2+4y^2=36 ?

The solution to (x-2)^2+4y^2=36 is Ellipse with (h,k)=(2,0),a=6,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-2)^2+4y^2=36

(x - 2)^{2} + 4 y^{2} = 36

(h, k) = (2, 0), a = 6, b = 3

Solution steps

(x - 2)^{2} + 4 y^{2} = 36

Rewrite

(x - 2)^{2} + 4 y^{2} = 36

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 0), a = 6, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, 0), a = 6, b = 3

6 x^{2} + 2 y^{2} + 18 x - 10 y + 2 = 0

16 x^{2} + 9 y^{2} - 128 x - 18 y + 121 = 0

\frac{( x - 2 ) ^{2}}{9} + \frac{y ^{2}}{7} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{36} = 1

\frac{x}{( x ^{2} + y ^{2} )} = \frac{1}{2}

What is (x-2)^2+4y^2=36 ?
The solution to (x-2)^2+4y^2=36 is Ellipse with (h,k)=(2,0),a=6,b=3