What is (x+5)^2=-18(y-3) ?

The solution to (x+5)^2=-18(y-3) is Parabola with (h,k)=(-5,3),p=-9/2

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(x+5)^2=-18(y-3)

(x + 5)^{2} = - 18 (y - 3)

(h, k) = (- 5, 3), p = - \frac{9}{2}

Solution steps

(x + 5)^{2} = - 18 (y - 3)

Rewrite

(x + 5)^{2} = - 18 (y - 3)

in the standard form:

4 (- \frac{9}{2}) (y - 3) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, 3), p = - \frac{9}{2}

x^{2} = 4 y + 4

x^{2} + 4 x + 4 y = 4

(x - 0)^{2} = 8 (y - 1)

x^{2} - 4 x + 2 k (x) = 0

x^{2} - 14 x - 12 y + 29 = 0

What is (x+5)^2=-18(y-3) ?
The solution to (x+5)^2=-18(y-3) is Parabola with (h,k)=(-5,3),p=-9/2