What is (x^2)/(256)+(y^2)/(400)=1 ?

The solution to (x^2)/(256)+(y^2)/(400)=1 is Ellipse with (h,k)=(0,0),a=16,b=20

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(x^2)/(256)+(y^2)/(400)=1

\frac{x ^{2}}{256} + \frac{y ^{2}}{400} = 1

(h, k) = (0, 0), a = 16, b = 20

Solution steps

\frac{x ^{2}}{256} + \frac{y ^{2}}{400} = 1

Rewrite

\frac{x ^{2}}{256} + \frac{y ^{2}}{400} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 6 ^{2}} + \frac{( y - 0 ) ^{2}}{2 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 16, b = 20

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 20, a = 16

\frac{( x - 1 ) ^{2}}{13} + \frac{( y + 5 ) ^{2}}{12} = 1

x^{2} + 2 y^{2} - 8 y - 32 = 0

\frac{x ^{2}}{324} + \frac{y ^{2}}{400} = 1

3 x^{2} + 4 y^{2} - 12 x = 36

6 x^{2} + 8 y^{2} = 48

What is (x^2)/(256)+(y^2)/(400)=1 ?
The solution to (x^2)/(256)+(y^2)/(400)=1 is Ellipse with (h,k)=(0,0),a=16,b=20