What is (y^2)/(16)+(x^2)/(25)=1 ?

The solution to (y^2)/(16)+(x^2)/(25)=1 is Ellipse with (h,k)=(0,0),a=5,b=4

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(y^2)/(16)+(x^2)/(25)=1

\frac{y ^{2}}{16} + \frac{x ^{2}}{25} = 1

(h, k) = (0, 0), a = 5, b = 4

Solution steps

\frac{y ^{2}}{16} + \frac{x ^{2}}{25} = 1

Rewrite

\frac{y ^{2}}{16} + \frac{x ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 5, b = 4

22 x^{2} + 2 y^{2} - 4 x + 12 y - 12 = 0

\frac{( x - 2 ) ^{2}}{\frac{2}{3}} + \frac{( y - 1 ) ^{2}}{16} = 1

3 x^{2} + 4 y^{2} - 5 x + 2 y + 1 = 0

\frac{x ^{2}}{36} + \frac{y ^{2}}{121} = 1

(x + 8)^{2} + (\frac{y + 1}{2})^{2} = 3

What is (y^2)/(16)+(x^2)/(25)=1 ?
The solution to (y^2)/(16)+(x^2)/(25)=1 is Ellipse with (h,k)=(0,0),a=5,b=4