What is ((x-1)^2)/(0.1^2)+((y-1)^2)/(0.5^2)=1 ?

The solution to ((x-1)^2)/(0.1^2)+((y-1)^2)/(0.5^2)=1 is Ellipse with (h,k)=(1,1),a=0.1,b=0.5

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((x-1)^2)/(0.1^2)+((y-1)^2)/(0.5^2)=1

\frac{( x - 1 ) ^{2}}{0. 1 ^{2}} + \frac{( y - 1 ) ^{2}}{0. 5 ^{2}} = 1

(h, k) = (1, 1), a = 0.1, b = 0.5

Solution steps

\frac{( x - 1 ) ^{2}}{0. 1 ^{2}} + \frac{( y - 1 ) ^{2}}{0. 5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 1), a = 0.1, b = 0.5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, 1), b = 0.5, a = 0.1

x^{2} + 2 y^{2} + 5 x - 2 y - 1 = 0

\frac{( x ^{2} )}{16} + \frac{( y ^{2} )}{25} = 1

(\frac{x ^{2}}{9}) + (\frac{y ^{2}}{16}) = 1

\frac{( x - 8 ) ^{2}}{12} + \frac{( y + 1 ) ^{2}}{16} = 1

16 x^{2} + 25 y^{2} + 160 x + 200 y + 400 = 0

What is ((x-1)^2)/(0.1^2)+((y-1)^2)/(0.5^2)=1 ?
The solution to ((x-1)^2)/(0.1^2)+((y-1)^2)/(0.5^2)=1 is Ellipse with (h,k)=(1,1),a=0.1,b=0.5