What is ((x-2)^2}{25}+\frac{(v+3)^2)/9 =1 ?

The solution to ((x-2)^2}{25}+\frac{(v+3)^2)/9 =1 is Ellipse with (h,k)=(2,-3),a=5,b=3

Popular >

((x-2)^2}{25}+\frac{(v+3)^2)/9 =1

\frac{( x - 2 ) ^{2}}{25} + \frac{( v + 3 ) ^{2}}{9} = 1

(h, k) = (2, - 3), a = 5, b = 3

Solution steps

\frac{( x - 2 ) ^{2}}{25} + \frac{( v + 3 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{25} + \frac{( v + 3 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{5 ^{2}} + \frac{( v - ( - 3 ) ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 3), a = 5, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, - 3), a = 5, b = 3

\frac{( x + 1 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{8 ^{2}} = 1

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{4} = 1

4 = x^{2} + 2 y^{2}

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{100} = 1

1^{2} = (x - 0)^{2} + (y - 1)^{2}

What is ((x-2)^2}{25}+\frac{(v+3)^2)/9 =1 ?
The solution to ((x-2)^2}{25}+\frac{(v+3)^2)/9 =1 is Ellipse with (h,k)=(2,-3),a=5,b=3