What is (x+9)^2-2(y-4)=0 ?

The solution to (x+9)^2-2(y-4)=0 is Parabola with (h,k)=(-9,4),p= 1/2

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(x+9)^2-2(y-4)=0

(x + 9)^{2} - 2 (y - 4) = 0

(h, k) = (- 9, 4), p = \frac{1}{2}

Solution steps

(x + 9)^{2} - 2 (y - 4) = 0

Rewrite

(x + 9)^{2} - 2 (y - 4) = 0

in the standard form:

4 \cdot \frac{1}{2} (y - 4) = (x - (- 9))^{2}

Therefore parabola properties are:

(h, k) = (- 9, 4), p = \frac{1}{2}

x + y^{2} = 25

y^{2} = x - 7

(y - 2)^{2} = 12 (x - 1)

4 x^{2} + 9 y = 36

y^{2} - 2 y - 16 x - 15 = 0

What is (x+9)^2-2(y-4)=0 ?
The solution to (x+9)^2-2(y-4)=0 is Parabola with (h,k)=(-9,4),p= 1/2