What is (x^2)/(20)+(y^2)/(36)=1 ?

The solution to (x^2)/(20)+(y^2)/(36)=1 is Ellipse with (h,k)=(0,0),a=2sqrt(5),b=6

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(x^2)/(20)+(y^2)/(36)=1

\frac{x ^{2}}{20} + \frac{y ^{2}}{36} = 1

(h, k) = (0, 0), a = 25, b = 6

Solution steps

\frac{x ^{2}}{20} + \frac{y ^{2}}{36} = 1

Rewrite

\frac{x ^{2}}{20} + \frac{y ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 5 ) ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 25, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 6, a = 25

\frac{( x + 1 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{1} = 1

4 (x - 3)^{2} + (y - 2)^{2} = 4

\frac{x ^{2} + y ^{2}}{x} = 16

4 x^{(2)} + 16 y^{(2)} - 16 x - 48 = 0

\frac{( x ^{2} )}{( 16 )} + \frac{( y ^{2} )}{( 12 )} = 1

What is (x^2)/(20)+(y^2)/(36)=1 ?
The solution to (x^2)/(20)+(y^2)/(36)=1 is Ellipse with (h,k)=(0,0),a=2sqrt(5),b=6