What is (x-5)^2+(y^2)/(25)=1 ?

The solution to (x-5)^2+(y^2)/(25)=1 is Ellipse with (h,k)=(5,0),a=1,b=5

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(x-5)^2+(y^2)/(25)=1

(x - 5)^{2} + \frac{y ^{2}}{25} = 1

(h, k) = (5, 0), a = 1, b = 5

Solution steps

(x - 5)^{2} + \frac{y ^{2}}{25} = 1

Rewrite

(x - 5)^{2} + \frac{y ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 5 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (5, 0), a = 1, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (5, 0), b = 5, a = 1

\frac{( x - 2 ) ^{2}}{3 ^{2}} + \frac{( y - 1 ) ^{2}}{2 ^{2}} = 1

\frac{( x ^{2} )}{9} + \frac{( y ^{2} )}{16} = 1

(\frac{x ^{2}}{64}) + (\frac{y ^{2}}{25}) = 1

1^{2} = (X - 0)^{2} + (Y - 1)^{2}

9 x^{2} + 16 y^{2} - 72 x + 32 y + 16 = 0

What is (x-5)^2+(y^2)/(25)=1 ?
The solution to (x-5)^2+(y^2)/(25)=1 is Ellipse with (h,k)=(5,0),a=1,b=5