What is 2x^2+3y^2-12x+12y+12=0 ?

The solution to 2x^2+3y^2-12x+12y+12=0 is Ellipse with (h,k)=(3,-2),a=3,b=sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2+3y^2-12x+12y+12=0

2 x^{2} + 3 y^{2} - 12 x + 12 y + 12 = 0

(h, k) = (3, - 2), a = 3, b = 6

Solution steps

2 x^{2} + 3 y^{2} - 12 x + 12 y + 12 = 0

Rewrite

2 x^{2} + 3 y^{2} - 12 x + 12 y + 12 = 0

in the form of the standard ellipse equation

\frac{( x - 3 ) ^{2}}{3 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{( 6 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (3, - 2), a = 3, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (3, - 2), a = 3, b = 6

\frac{y ^{2}}{4} + \frac{z ^{2}}{9} = 1

2 x^{2} + y^{2} - 2 x \leq 0

\frac{( x + 7 ) ^{2}}{6} + \frac{( y + 7 ) ^{2}}{5} = 1

4 x^{2} - 16 + y^{2} + 2 y = - 1

9 x^{2} + 49 y^{2} = 1

What is 2x^2+3y^2-12x+12y+12=0 ?
The solution to 2x^2+3y^2-12x+12y+12=0 is Ellipse with (h,k)=(3,-2),a=3,b=sqrt(6)