What is ((x-4)^2)/(5^2)+((y-7)^2)/(3^2)=1 ?

The solution to ((x-4)^2)/(5^2)+((y-7)^2)/(3^2)=1 is Ellipse with (h,k)=(4,7),a=5,b=3

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((x-4)^2)/(5^2)+((y-7)^2)/(3^2)=1

\frac{( x - 4 ) ^{2}}{5 ^{2}} + \frac{( y - 7 ) ^{2}}{3 ^{2}} = 1

(h, k) = (4, 7), a = 5, b = 3

Solution steps

\frac{( x - 4 ) ^{2}}{5 ^{2}} + \frac{( y - 7 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (4, 7), a = 5, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (4, 7), a = 5, b = 3

9 x^{2} + 25 y^{2} + 18 x - 50 y = 191

\frac{x ^{2}}{9} + \frac{x ^{2}}{16} + \frac{z ^{2}}{9} = 1

9 x^{2} + 4 y^{2} - 72 x - 16 y + 124 = 0

8 x^{2} + 9 y^{2} + 24 x + 18 y = 10

x^{2} + y^{2} + 5 y = 0

What is ((x-4)^2)/(5^2)+((y-7)^2)/(3^2)=1 ?
The solution to ((x-4)^2)/(5^2)+((y-7)^2)/(3^2)=1 is Ellipse with (h,k)=(4,7),a=5,b=3