What is x^2+((y-6)^2)/(16)=1 ?

The solution to x^2+((y-6)^2)/(16)=1 is Ellipse with (h,k)=(0,6),a=1,b=4

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x^2+((y-6)^2)/(16)=1

x^{2} + \frac{( y - 6 ) ^{2}}{16} = 1

(h, k) = (0, 6), a = 1, b = 4

Solution steps

x^{2} + \frac{( y - 6 ) ^{2}}{16} = 1

Rewrite

x^{2} + \frac{( y - 6 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 6 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 6), a = 1, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 6), b = 4, a = 1

x^{2} + (3 y - 3)^{2} = 4

(x - 5)^{2} + 2 (y - 6)^{2} = 36

9 y^{2} = 144 - 16 x^{2}

x^{2} + 4 y^{2} + 10 x + 9 y - 7 = 0

16 x^{2} + 9 y^{2} - 32 x + 90 y + 145 = 0

What is x^2+((y-6)^2)/(16)=1 ?
The solution to x^2+((y-6)^2)/(16)=1 is Ellipse with (h,k)=(0,6),a=1,b=4