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Popular >

((x^2)/4)+y^2=1

Solution

(\frac{x ^{2}}{4}) + y^{2} = 1

Solution

(h, k) = (0, 0), a = 2, b = 1

Solution steps

\frac{x ^{2}}{4} + y^{2} = 1

Rewrite

\frac{x ^{2}}{4} + y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 1

Popular Examples

((x-5)^2}{2^2}+\frac{(y-3)^2)/9 =1

\frac{( x - 5 ) ^{2}}{2 ^{2}} + \frac{( y - 3 ) ^{2}}{9} = 1

25x^2+9y^2+100x-125=0

25 x^{2} + 9 y^{2} + 100 x - 125 = 0

1/(x+iy)+1/(x-iy)<-1

\frac{1}{x + i y} + \frac{1}{x - i y} < - 1

1/2 (x-y)^2+1/2 (x-y)(x+y)+1/2 (x+y)^2=4

\frac{1}{2} (x - y)^{2} + \frac{1}{2} (x - y) (x + y) + \frac{1}{2} (x + y)^{2} = 4

6x^2+9y^2-24x-54y+51=0

6 x^{2} + 9 y^{2} - 24 x - 54 y + 51 = 0

Frequently Asked Questions (FAQ)

What is ((x^2)/4)+y^2=1 ?
The solution to ((x^2)/4)+y^2=1 is Ellipse with (h,k)=(0,0),a=2,b=1