What is ((x+7)/(16))^2+((y+5)^2)/(16)=1 ?

The solution to ((x+7)/(16))^2+((y+5)^2)/(16)=1 is Ellipse with (h,k)=(-7,-5),a=16,b=4

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((x+7)/(16))^2+((y+5)^2)/(16)=1

(\frac{x + 7}{16})^{2} + \frac{( y + 5 ) ^{2}}{16} = 1

(h, k) = (- 7, - 5), a = 16, b = 4

Solution steps

(\frac{x + 7}{16})^{2} + \frac{( y + 5 ) ^{2}}{16} = 1

Rewrite

(\frac{x + 7}{16})^{2} + \frac{( y + 5 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 7 ) ) ^{2}}{1 6 ^{2}} + \frac{( y - ( - 5 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 7, - 5), a = 16, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 7, - 5), a = 16, b = 4

3 x^{2} + 2 y^{2} + 12 x - 8 y - 16 = 0

16 x^{2} + 25 y^{2} = 1.6

4 X^{2} + 9 Y^{2} - 32 X - 36 Y + 64 = 0

16 x^{2} + 9 y^{2} + 160 x + 18 y + 265 = 0

(\frac{x ^{2}}{16}) + (\frac{y ^{2}}{9}) = 1

What is ((x+7)/(16))^2+((y+5)^2)/(16)=1 ?
The solution to ((x+7)/(16))^2+((y+5)^2)/(16)=1 is Ellipse with (h,k)=(-7,-5),a=16,b=4