What is (y^2}{16}+\frac{(x+1)^2)/9 =1 ?

The solution to (y^2}{16}+\frac{(x+1)^2)/9 =1 is Ellipse with (h,k)=(-1,0),a=3,b=4

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(y^2}{16}+\frac{(x+1)^2)/9 =1

\frac{y ^{2}}{16} + \frac{( x + 1 ) ^{2}}{9} = 1

(h, k) = (- 1, 0), a = 3, b = 4

Solution steps

\frac{y ^{2}}{16} + \frac{( x + 1 ) ^{2}}{9} = 1

Rewrite

\frac{y ^{2}}{16} + \frac{( x + 1 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 0), a = 3, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, 0), b = 4, a = 3

3 x^{2} + 5 y^{2} = 15

\frac{( x - 1 ) ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

8 x^{2} + 9 y^{2} - 16 x - 18 y - 55 = 0

\frac{x ^{2}}{576} + \frac{y ^{2}}{676} = 1

9 x^{2} + y^{2} - 18 x - 6 y + 9 = 0

What is (y^2}{16}+\frac{(x+1)^2)/9 =1 ?
The solution to (y^2}{16}+\frac{(x+1)^2)/9 =1 is Ellipse with (h,k)=(-1,0),a=3,b=4