What is x^2+((y^2)/4)=1 ?

The solution to x^2+((y^2)/4)=1 is Ellipse with (h,k)=(0,0),a=1,b=2

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x^2+((y^2)/4)=1

x^{2} + (\frac{y ^{2}}{4}) = 1

(h, k) = (0, 0), a = 1, b = 2

Solution steps

x^{2} + \frac{y ^{2}}{4} = 1

Rewrite

x^{2} + \frac{y ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 2, a = 1

4 = 4 x^{2} + y^{2} + 1

\frac{( x + 4 ) ^{2}}{25} + \frac{( y - 2 ) ^{2}}{9} = 1

\frac{x ^{2}}{1} + \frac{y ^{2}}{15} = 1

9 x^{2} + 16 y^{2} + 72 x = 0

x^{2} + 8 y^{2} + 54 x - 48 y + 8 = 0

What is x^2+((y^2)/4)=1 ?
The solution to x^2+((y^2)/4)=1 is Ellipse with (h,k)=(0,0),a=1,b=2