What is 2y^2+x^2-2x-4=0 ?

The solution to 2y^2+x^2-2x-4=0 is Ellipse with (h,k)=(1,0),a=sqrt(5),b=sqrt(5/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2y^2+x^2-2x-4=0

2 y^{2} + x^{2} - 2 x - 4 = 0

(h, k) = (1, 0), a = 5, b = \frac{5}{2}

Solution steps

2 y^{2} + x^{2} - 2 x - 4 = 0

Rewrite

2 y^{2} + x^{2} - 2 x - 4 = 0

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{( 5 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{5}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 0), a = 5, b = \frac{5}{2}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 0), a = 5, b = \frac{5}{2}

x^{2} + 2 x + 4 y^{2} - 12 y + 7 = 0

78 = 32 (x - \frac{3}{2})^{2} + 50 (y + 1)^{2}

x^{2} + 2 y^{2} - 3 x + 8 y - 1 = 0

7 x^{2} = 35 - 5 y^{2}

4 x^{2} + 3 y^{2} = 25

What is 2y^2+x^2-2x-4=0 ?
The solution to 2y^2+x^2-2x-4=0 is Ellipse with (h,k)=(1,0),a=sqrt(5),b=sqrt(5/2)