What is 4x^2+3y^2=26 ?

The solution to 4x^2+3y^2=26 is Ellipse with (h,k)=(0,0),a=sqrt(13/2),b=sqrt(26/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2+3y^2=26

4 x^{2} + 3 y^{2} = 26

(h, k) = (0, 0), a = \frac{13}{2}, b = \frac{26}{3}

Solution steps

4 x^{2} + 3 y^{2} = 26

Rewrite

4 x^{2} + 3 y^{2} = 26

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{13}{2} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{26}{3} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{13}{2}, b = \frac{26}{3}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = \frac{26}{3}, a = \frac{13}{2}

9 x^{2} + 8 y^{2} = 3

4 x^{2} + 3 y^{2} = 30

2 x^{2} + 8 y^{2} - 128 = 0

x^{2} + y^{2} = - y

25 x^{2} + 9 y^{2} - 150 x - 36 y + 36 = 0

What is 4x^2+3y^2=26 ?
The solution to 4x^2+3y^2=26 is Ellipse with (h,k)=(0,0),a=sqrt(13/2),b=sqrt(26/3)