What is (x^2)/(36)+(y^2)/(5.91^2)=1 ?

The solution to (x^2)/(36)+(y^2)/(5.91^2)=1 is Ellipse with (h,k)=(0,0),a=6,b=5.91

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(x^2)/(36)+(y^2)/(5.91^2)=1

\frac{x ^{2}}{36} + \frac{y ^{2}}{5.9 1 ^{2}} = 1

(h, k) = (0, 0), a = 6, b = 5.91

Solution steps

\frac{x ^{2}}{36} + \frac{y ^{2}}{5.9 1 ^{2}} = 1

Rewrite

\frac{x ^{2}}{36} + \frac{y ^{2}}{5.9 1 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{5.9 1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 5.91

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 6, b = 5.91

16 x^{2} + 25 y^{2} - 128 x + 100 y = 0

\frac{( ( x + 0 ) ^{2} )}{40} + \frac{( ( y + 0 ) ^{2} )}{32} = 1

\frac{( x - 5 ) ^{2}}{16} + \frac{( y + 15 ) ^{2}}{25} = 1

\frac{x}{x ^{2} + y ^{2}} = \frac{1}{2}

\frac{x ^{2}}{3. 5 ^{2}} + \frac{y ^{2}}{2. 5 ^{2}} = 1

What is (x^2)/(36)+(y^2)/(5.91^2)=1 ?
The solution to (x^2)/(36)+(y^2)/(5.91^2)=1 is Ellipse with (h,k)=(0,0),a=6,b=5.91